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Derivative Of X Sinx

Introduction to derivative:

Introduction to derivative:

In mathematics, we study different topics. Derivative is one of the part mostly used in calculus. Derivative is also known as differentiation. Derivative is used for finding the rate of change of the function. The derivative of the function z is denoted as z'. Different variables and functions are used in derivatives. Different formulas are used for finding the derivative values.

Derivative formulas:

'(d)/(dx) (x^y) = yx^(y-1)'

'(d)/(dx) x = 1'

'(d)/(dx) (2) = 0'

'(d)/(dx) (uv) = u((dv)/(dx)) + v((du)/(dx))'

Example Problems for Derivative of X Sinx

Derivative example problem 1:

Find the first derivative value of the given function f(x) = x sinx.

Solution:

Given function is f(x) = x sinx

Using the formula, we differentiate the given function

'(d)/(dx) (uv) = u ((dv)/(dx)) + v ((du)/(dx))'

From the given function

u = x and v = sinx

Differentiate the above values with respect to x, we get

du = 1 dx and dv = cosx dx

Substitute the given values in the above formula, we get

'(d)/(dx) (uv)' = x (cosx) + sinx (1)

= xcosx + sinx

Answer:

The final answer is xcosx + sinx

Derivative example problem 2:

Find the first derivative value of the given function f(x) = 2x sinx.

Solution:

Given function is f(x) = 2x sinx

Using the formula, we differentiate the given function

'(d)/(dx) (uv) = u ((dv)/(dx)) + v ((du)/(dx))'

From the given function

u = 2x and v = sinx

Differentiate the above values with respect to x, we get

du = 2 dx and dv = cosx dx

Substitute the given values in the above formula, we get

' (d)/(dx) (uv)' = x (cosx) + sinx (2)

= xcosx + 2sinx

Answer:

The final answer is xcosx + 2sinx

Derivative Example Problem 3:

Find the first derivative value of the given function f(x) = x 3sinx.

Solution:

Given function is f(x) = x 3sinx

Using the formula, we differentiate the given function

'(d)/(dx) (uv) = u ((dv)/(dx)) + v ((du)/(dx))'

From the given function

u = x and v = 3sinx

Differentiate the above values with respect to x, we get

du = 1 dx and dv = 3cosx dx

Substitute the given values in the above formula, we get

'(d)/(dx) (uv)' = x (3cosx) + sinx (1)

= 3xcosx + sinx

Answer:

The final answer is 3xcosx + sinx

by: jeri
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