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Probability Math Problems

Probability Math Problems

Probability Math Problems

Probability in math is the chance of the outcome of an event of a particular experiment. Probabilities are occurs always numbers between 0 (impossible) and 1(possible). The set of all possible outcomes of a particular experiment is called as sample space. For example probability of getting a 2 when rolling a dice is 1/6. In this lesson we will discuss about how to solve the probability math problems.

Probability Math Problems - Example Problems

Example:1 In a box there are 18 candies, 10 of which are lemon, 4 are apple and 4 are orange candies. Find the probability of:

a) lemon candy drawing first.

b) apple candy drawing second after lemon candy had drawn.

c) orange candy drawing third if one apple candy and one orange candy had drawn.

Sol:

a) Let S = Sample space, n(S) = 10 + 4 + 4 = 18

A be the event of lemon candy drawing first, n(A) = 10

Probability of a lemon candy drawing first:

P(A) = '(n(A))/(n(S))' = '10/18' = '5/9'

b) Let B be the event of a apple candy drawing second from remaining 17 candies, n(B) = 4

Probability of a apple candy drawing second:

P(B) = '(n(B))/(n(S))' = '4/17'

c) If one lemon and apple candy had drawn, then there would be 16 candies remaining, 4 of which are orange candies. Let S1 be the sample space and C be the event of a orange candy drawing third.

n(S1) = 16

n(C) = 4

Probability of a orange candy drawing after one lemon and apple candy has drawn

P(C) =' (n(C))/(n(S1)) ' = '4/16' = '1/4' .

Example:2 A box contains 5 brown socks, 5 black socks. If 2 socks are drawn at random, find the probability that both are brown or black socks.

Sol:

We have to select 2 socks from 5 + 5 = 10 socks.

n(S) = 10C2 = '(10!)/(2!xx8!) ' = '(10xx9)/(2xx1)' = '90/2' = 45

Let A be the event of drawing 2 brown socks.

B be the event of drawing 2 black socks.

n(A) = 5C2 = '(5!)/(2!xx3!) ' = '(5xx4)/2' = 10

n(B) = 5C2 =' (5!)/(2!xx3!) ' = '(5xx4)/2' = 10

P(A) =' (n(A))/(n(S))' = '10/45 = 2/9'

P(B) = '(n(B))/(n(S))' = '10/45 = 2/9'

P(A or B) = P(A) + (B) = '2/9' + '2/9' ='4/9'

P(A or B) = '4/9' .

Probability Math Problems - Practice Problems

Solve these practice math probability word problems.

Pr:1 In a box there are 15 marbles, 6 of which are black, 9 are brown. Find the probability of:

a) black marble drawing first.

b) brown marble drawing second after black had drawn.

Pr:2 A box contains 10 brown and 5 black socks. If two socks are drawn at random, find the probability that 1 is blrown and 1 is black socks.

Answer: 1) a) '2/5' , b) '3/5 ' 2) '11/21'

by: Omkar Nayak
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