Solve Constant Term

Constant term is the term which has a fixed value (such as 4

, 6.5, 3/4, pi, or the square root of 5) and it does not solve any variable. If there is no such term in an expression or equation then the constant term is taken as 0. Every polynomial equation in standard form has unique constant term is considered as x0. The constant term always has the lowest degree term.

Evaluation to Solve Constant Term:

Let us considered an expression,

ax^2 + bx + c = d.

Now modify the above expression as

ax^2 + bx = d c.

We have four terms in the above expression. Generally the term which does not have any variables is refereed as Constant term. The first and second terms in the left side has the variables (x^2, x) while the third and fourth term (c, d) in the right side does not contain any variables with it. So, the variables d and -c is the constant term.

Understand cbse last year question paper is always challenging for me but thanks to all math websites to help me out.

For example,

In the equation,

x^2 + 5x + 6 = 7.

Simplify the equation x^2 + 5x + 6 = 7

x^2 + 5x = 7 - 6

x^2 + 5x = 1

Here the third term 1 is the constant term.

Examples on Solving Constant Term:

Q:1 Find and solve the constant term in the equation 9x^2 - 8x +1.

Sol:

In the equation 9x^2 - 8x + 1, the first two terms has the variables like x^2 and x.

The third term does not have any variables.

Generally the term which does not contain any variable is referred as constant term,

So, the third term 1 is the constant term in the expression 9x^2 - 8x +1.

Q:2 Find the constant term in the equation 9x^3 - 8x^2 +7x - 6.

Sol:

In the polynomial equation, 9x^3 - 8x^2 + 7x - 6.

Solve the equation of 9x^3 - 8x^2 + 7x - 6

All the first three terms has variable like x^3, x^2, x.

But the fourth term does not have any variables.

So, - 6 is the Constant term in the expression p(x) = 9x^3 - 8x^2 + 7x - 6.

by: johnharmer

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