Variable Expression From Math
In mathematics, an expression is a finite combination of symbols that are well formed according to the rules applicable in the context at hand
. Symbols can designate values (constants), variables, operations, relations, or can constitute punctuation or other syntactic entities. The use of expression can range from simple arithmetic operations like
'3+5 xx ((-2)^(7)- (3)/(2))'
Source: Wikipedia
Rules for Solving Variable Expression from Math:
Rule 1: To solve variable expression from math.
Step 1: set the terms containing the identical variable collectively in study pre-calculus expression.
Step 2: succeed the operation inside the parentheses for the variable and other.
Step 3: revise the study pre-calculus expression and simplify pre-calculus expression.
Step 4: To make sure the equation, if there is able to simplify the pre-calculus simplify expression and then repeat the step 1 to 4.
Rule 2: order of operation for solves variable expression from math.
In long math problems with +,-,x,%,(), and exponents in them, you have to identify what to do first. Without follow the same rules, you may get unlike answers. You can easily keep in mind the silly sentence, Big Elephants Destroy Mice And Snails, you can commit to memory the order of operations, and you must follow.
Big "B" means Brackets. We need to carry out operation in side parentheses first.
Elephants "E" means an exponent, you must calculate exponents next.
Destroy "D" means division. Begin on the left of the equation and perform all multiplication and divisions in the order in which they appear.
Mice "M" means multiply
And "A" means addition.
Snails "S" means subtract. For all time on the left hand side and accomplish additions and subtractions operation.
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Example Problems for Variable Expression from Math:
To solve variable expression from math using above rules, 8P^2+9Q^2+11P^2-6-7R2-7Q^2+2Q^2+7R2+2
Solution:
Step 1: Is to group like terms. Set of terms containing the same variable together. Set of constants together.
(8P^2+11P^2)+(9Q^2-7Q^2+2Q^2)+(-7R2+7R2)+(-6+2)
Step 2: Is to carry on the operation inside the parentheses for the variable P.
(8P^2+11P^2)=(8+11)'xx'P^2=19 'xx' P^2=19P^2
Step 3: Is to carry on the operation inside the parentheses for the variable Q.
(9Q^2-7Q^2+2Q^2)=(9-7+2)Q^2=(11-7) 'xx' Q^2 =4 'xx' Q^2=4Q^2
Step 4: Is to carry on the operation inside the parentheses for the variable R.
(-7R2+7R2)=(-7+7)R2=0 'xx' R2=0
Step 5: Is to carry on the operation inside the parentheses for the constants.
-6+2=-4
Step 6: Is to adjust the expression.
Therefore, we get 19P^2+4Q^2-4
Since the left over terms are not like terms, the problem cannot be any further.
The correct answer is 19P^2+4Q^2-4
by: johnharmer
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