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subject: Quadratic Formula Problem [print this page]


Introduction to quadratic formula problem:

Definition:

An equation in which the highest power of the variable is 2 is called a quadratic equation.

ax^2+bx+c=0, where a, b, c are constants, is a general quadratic equation.

Any grouping of constants and variables generated by applying finite number of the elementary operations-addition, subtraction, multiplication, division, or the extraction of roots -is called an algebraic expression. For example,

$frac{3x^{4}+5x^{2}-sqrt{2x+4}}{9}$, $xy^{2}+5x^{2}z-sqrt[3]{z}$, etc.

are algebraic expressions. Thus, ax^2+bx+c is also an algebraic expression.

Quadratic expression in One variable(or unknown)

A polynomial of the form ax^2+bx+c(a'!=' 0) is called a quadratic expression in the variable x. This is a polynomial of the second degree.

For example, (i) 5x^2-7x+2 and (ii)2x^2+1 are quadratic expressions in x.

But $frac{6}{x^{2}}-frac{1}{x}+7$ is a quadratic expression in 1/x, and 9x-2 is not a quadratic expression.

In the quadratic expression ax^2+bx+c, a is co-efficient of x^2, b is the co-efficient of x and c is the constant term.

Classification of Quadratic equations:

Quadratic equations are classified into two categories:

(i) Pure quadratic equations(of the form ax^2+c=0, i.e., b=0 in ax^2+bx+c=0)

(ii) Affected (or affected) quadratic equations(of the form ax^2+bx+c=0, b'!=' 0).

For example, (i)x^2-4=0 and (ii)3x^2-1=0 are pure quadratic equations, while (iii) x^2-2x-8=0 and (iv) 3x^2+x=0 are affected quadratic equations.

Quadratic Formula for the Std Equation

Solution of the equation ax^2+bx+c=0

Proof:

ax^2+bx+c=0 (a'!=' 0)

ax^2+bx=-c (transposing the constant term)

x^2+'(b)/(a)' x= '(-c)/(a)' (dividing by the co-efficients of x^2)

x^2+'(b)/(a)' x+$frac{b^{2}}{4a^{2}}$ = $frac{b^{2}}{4a^{2}}$-'(c)/(a)'

(Adding $frac{b^{2}}{4a^{2}}$ to both sides to make L.H.S. a perfect square.)

(x+'(b)/(2a)' )2 = $frac{b^{2}-4ac}{4a^{2}}$

or x+'(b)/(2a)' = $frac{pm sqrt{b^{2}-4ac}}{2a}$

$mathbf{x=frac{-bpm sqrt{b^{2}-4ac}}{2a}}$

Hence, the roots of the equation ax^2+bx+c=0 are

$mathbf{frac{-b+ sqrt{b^{2}-4ac}}{2a}}$ and $mathbf{frac{-b- sqrt{b^{2}-4ac}}{2a}}$

The roots of the equation are also called the zeros of the function defined by f(x)=ax^2+bx+c.

Check this awesome Properties of Matrices i recently used.

Problems Solved Using Quadratic Formula:

Pro 1: Solve: 2x^2+2x-3=0.

Sol: Here a=2, b=2, c=-3

Using $mathbf{x=frac{-bpm sqrt{b^{2}-4ac}}{2a}}$, we get

x= $mathbf{x=frac{-2pm sqrt{2^{2}-4times 2times (-3))}}{2times 2}}= frac{-2pm sqrt{4+24}}{4}$

= $frac{-2pm sqrt{28}}{4}$ = $frac{-2pm 2sqrt{7}}{4}$

= $frac{-1pm sqrt{7}}{2}$

x= $frac{-1+sqrt{7}}{2}$ and $frac{-1-sqrt{7}}{2}$

Practice problems:

1. 6x^2+7x-20=0

[Ans: $1frac{1}{3}, -2frac{1}{2}$]

2. 15x^2-28=x.

[Ans: $1frac{2}{5}, -1frac{1}{3}$]

by: Smith




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