subject: Open Problems In Statistics [print this page] Introduction to open problems in statistics:
Open problems in statistics are the learning about the mean, mode, median and also the range. The open problems in statistics are the term of the design of the survey and also the experiments. Open problems in statistics are the process that the tutor explains the procedure in the online by the step by step procedure for the mathematical all problems. Open problems in statistics refer the quantities find for the data. Open problems in statistics include the collection, analysis and also the interpretation.
Examples for the Open Problems in Statistics:
Example 1 to the open problems in statistics:
Predict the mean, mode and the median for the data 7104, 7106, 7101, 7106, 7103.
Solution:
The given set of data is 7104, 7106, 7101, 7106, 7103.
The formula used to resolve mean = '(t1+t2+t3+. . . . . .+t x)/x'
Step 1: Mean = '(7104+7106+7101+7106+7103)/5'
Step 2: Mean = '35520/5'
Step 3: Mean = 7104
Step 4: 7101, 7103, 7104, 7106, 7106. (Given set of data arranged in the ascending order)
Step 5: Median = 7104
Step 6: Mode = 7106 (Frequently placed data)
The mean value for the set of data 7104, 7106, 7101, 7106, 7103 is 7104. The median for the given set of data is 7104 and mode is 7106.
Example 2 to the open problems in statistics:
Find the mean, mode and median for the data 9009, 9004, 9005, 9004, 9007.
Solution:
The given set of data is 9009, 9004, 9005, 9004, 9007.
The formula used to resolve mean = '(t1+t2+t3+. . . . . .+t x)/x'
Step 1: Mean = '(9009+9004+9005+9004+9007)/5'
Step 2: Mean = '45029/5'
Step 3: Mean = 9005.8
Step 4: 9004, 9004, 9005, 9007, 9009. (Given set of data arranged in the ascending order)
Step 5: Median = 9005
Step 6: Mode = 9004 (Frequently placed data)
The mean value for the set of data 9009, 9004, 9005, 9004, 9007 is 9005.8. The median for the given set of data is 9005 and the mode is 9004.
Example 3 to the open problems in statistics:
Compute the mean, mode and median for the given set of data 2815, 2819, 2813, 2817, 2813, 2812.
Solution:
The given set of data is 2815, 2819, 2813, 2817, 2813, 2812.
The formula used to resolve mean = '(t1+t2+t3+. . . . . .+t x)/x'
Step 1: Mean = '(2815+2819+2813+2817+2813+2812)/6'
Step 2: Mean = '16889/6'
Step 3: Mean = 2814.8
Step 4: 2812, 2813, 2813, 2815, 2817, 2819. (Given set of data arranged in the ascending order)
Step 5: Median = '(2043+2045)/2' = 2044
Step 6: Mode = 2043 (Frequently placed data)
The mean for the set of data 2815, 2819, 2813, 2817, 2813, 2812 is 2814.8. The median for the given set of data is 2814 and the mode is 2813.
Practice Problem for the Open Problems in Statistics:
Estimate the mean, mode and median for the set of data 5531, 5536, 5533, 5535, 5536.
Answer: mean = 5534.2, median = 5535, mode = 5536.
Determine the mean, mode and median for the data 8079, 8074, 8070, 8075, 8078, 8073, 8077, 8073.
Answer: mean = 8074.875, median = 8074.5, mode = 8073.
